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13x^2-30x+8=0
a = 13; b = -30; c = +8;
Δ = b2-4ac
Δ = -302-4·13·8
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-22}{2*13}=\frac{8}{26} =4/13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+22}{2*13}=\frac{52}{26} =2 $
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